Optimal. Leaf size=191 \[ -\frac{3 a \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )}{2 c}+\frac{3 a \text{PolyLog}\left (4,\frac{2}{a x+1}-1\right )}{4 c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{2 c}-\frac{3 a \tanh ^{-1}(a x) \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{c}+\frac{3 a \tanh ^{-1}(a x) \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )}{2 c}+\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}-\frac{a \log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^3}{c}+\frac{3 a \log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^2}{c} \]
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Rubi [A] time = 0.463386, antiderivative size = 191, normalized size of antiderivative = 1., number of steps used = 10, number of rules used = 8, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {5934, 5916, 5988, 5932, 5948, 6056, 6610, 6060} \[ -\frac{3 a \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )}{2 c}+\frac{3 a \text{PolyLog}\left (4,\frac{2}{a x+1}-1\right )}{4 c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{2 c}-\frac{3 a \tanh ^{-1}(a x) \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )}{c}+\frac{3 a \tanh ^{-1}(a x) \text{PolyLog}\left (3,\frac{2}{a x+1}-1\right )}{2 c}+\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}-\frac{a \log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^3}{c}+\frac{3 a \log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x)^2}{c} \]
Antiderivative was successfully verified.
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Rule 5934
Rule 5916
Rule 5988
Rule 5932
Rule 5948
Rule 6056
Rule 6610
Rule 6060
Rubi steps
\begin{align*} \int \frac{\tanh ^{-1}(a x)^3}{x^2 (c+a c x)} \, dx &=-\left (a \int \frac{\tanh ^{-1}(a x)^3}{x (c+a c x)} \, dx\right )+\frac{\int \frac{\tanh ^{-1}(a x)^3}{x^2} \, dx}{c}\\ &=-\frac{\tanh ^{-1}(a x)^3}{c x}-\frac{a \tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )}{c}+\frac{(3 a) \int \frac{\tanh ^{-1}(a x)^2}{x \left (1-a^2 x^2\right )} \, dx}{c}+\frac{\left (3 a^2\right ) \int \frac{\tanh ^{-1}(a x)^2 \log \left (2-\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{c}\\ &=\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}-\frac{a \tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )}{c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{(3 a) \int \frac{\tanh ^{-1}(a x)^2}{x (1+a x)} \, dx}{c}-\frac{\left (3 a^2\right ) \int \frac{\tanh ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{c}\\ &=\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}+\frac{3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{a \tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )}{c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{3 a \tanh ^{-1}(a x) \text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{2 c}-\frac{\left (3 a^2\right ) \int \frac{\text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{2 c}-\frac{\left (6 a^2\right ) \int \frac{\tanh ^{-1}(a x) \log \left (2-\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{c}\\ &=\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}+\frac{3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{a \tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{3 a \tanh ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{3 a \tanh ^{-1}(a x) \text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{3 a \text{Li}_4\left (-1+\frac{2}{1+a x}\right )}{4 c}+\frac{\left (3 a^2\right ) \int \frac{\text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx}{c}\\ &=\frac{a \tanh ^{-1}(a x)^3}{c}-\frac{\tanh ^{-1}(a x)^3}{c x}+\frac{3 a \tanh ^{-1}(a x)^2 \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{a \tanh ^{-1}(a x)^3 \log \left (2-\frac{2}{1+a x}\right )}{c}-\frac{3 a \tanh ^{-1}(a x) \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{c}+\frac{3 a \tanh ^{-1}(a x)^2 \text{Li}_2\left (-1+\frac{2}{1+a x}\right )}{2 c}-\frac{3 a \text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{3 a \tanh ^{-1}(a x) \text{Li}_3\left (-1+\frac{2}{1+a x}\right )}{2 c}+\frac{3 a \text{Li}_4\left (-1+\frac{2}{1+a x}\right )}{4 c}\\ \end{align*}
Mathematica [C] time = 0.289606, size = 154, normalized size = 0.81 \[ \frac{a \left (-\frac{3}{2} \left (\tanh ^{-1}(a x)-2\right ) \tanh ^{-1}(a x) \text{PolyLog}\left (2,e^{2 \tanh ^{-1}(a x)}\right )+\frac{3}{2} \left (\tanh ^{-1}(a x)-1\right ) \text{PolyLog}\left (3,e^{2 \tanh ^{-1}(a x)}\right )-\frac{3}{4} \text{PolyLog}\left (4,e^{2 \tanh ^{-1}(a x)}\right )+\frac{1}{2} \tanh ^{-1}(a x)^4-\frac{\tanh ^{-1}(a x)^3}{a x}-\tanh ^{-1}(a x)^3-\tanh ^{-1}(a x)^3 \log \left (1-e^{2 \tanh ^{-1}(a x)}\right )+3 \tanh ^{-1}(a x)^2 \log \left (1-e^{2 \tanh ^{-1}(a x)}\right )-\frac{\pi ^4}{64}+\frac{i \pi ^3}{8}\right )}{c} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 0.536, size = 1451, normalized size = 7.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{{\left (a x \log \left (a x + 1\right ) - 1\right )} \log \left (-a x + 1\right )^{3}}{8 \, c x} + \frac{1}{8} \, \int \frac{{\left (a x - 1\right )} \log \left (a x + 1\right )^{3} - 3 \,{\left (a x - 1\right )} \log \left (a x + 1\right )^{2} \log \left (-a x + 1\right ) - 3 \,{\left (a^{2} x^{2} + a x -{\left (a^{3} x^{3} + a^{2} x^{2} + a x - 1\right )} \log \left (a x + 1\right )\right )} \log \left (-a x + 1\right )^{2}}{a^{2} c x^{4} - c x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\operatorname{artanh}\left (a x\right )^{3}}{a c x^{3} + c x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{\operatorname{atanh}^{3}{\left (a x \right )}}{a x^{3} + x^{2}}\, dx}{c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{artanh}\left (a x\right )^{3}}{{\left (a c x + c\right )} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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